#include<bits/stdc++.h> using namespace std; int x,y,n; int main() { cin>>x>>y; for(int m=1;m<=x;m++){ int n=x-m; if((2m+4n)==y) cout<<m<<' '<<n; } return 0; } /* 1.鸡兔共x只,设鸡m只,则兔为(x-m)只,则:

2m+4(x-m)=y

*/